Questions/D & F Block/Why is the $$E^\circ...
Standard Electrode Potentials (E°)D & F Block

Why is the E(M3+/M2+)E^\circ (M^{3+}/M^{2+})value for Scandium very low?.

Expert Answer

Sc3+Sc^{3+} has a stable noble gas configuration. Sc2+Sc^{2+} would instantly lose an electron to reach this state.

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