JEE Main · 2021 · Shift-IImediumBIO-137

Identify the reagent(s) 'A' and condition(s) for the reaction

Biomolecules · Class 12 · JEE Main Previous Year Question

Question

image Identify the reagent(s) 'A' and condition(s) for the reaction

Options
  1. a

    A=\ceHCl\text{A} = \ce{HCl}; Anhydrous \ceAlCl3\ce{AlCl3}

  2. b

    A=\ceCl2\text{A} = \ce{Cl2}; UV light

  3. c

    A=\ceCl2\text{A} = \ce{Cl2}; dark, Anhydrous \ceAlCl3\ce{AlCl3}

  4. d

    A=\ceHCl\text{A} = \ce{HCl}, \ceZnCl2\ce{ZnCl2}

Correct Answerb

A=\ceCl2\text{A} = \ce{Cl2}; UV light

Detailed Solution

Step 1: Identifying the Reaction Type — Benzene reacts with chlorine to form benzene hexachloride (BHC / Lindane) under specific conditions.

Step 2: Analyzing Conditions — This is a free radical addition reaction. It requires the presence of chlorine gas and ultraviolet (UV) light to generate the necessary radicals.

Step 3: Result Selection — Therefore, the reagent 'A' is chlorine gas and the condition is UV light. Correct option is (b).

Key Point: This reaction saturates all double bonds in the benzene ring to yield the non-aromatic product C6H6Cl6C_6H_6Cl_6.

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