JEE Main · 2022 · Shift-IImediumBOND-076

Identify the incorrect statement for PCl5 from the following:

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Identify the incorrect statement for PCl5\mathrm{PCl_5} from the following:

Options
  1. a

    In this molecule, orbitals of phosphorus are assumed to undergo sp3d\mathrm{sp^3d} hybridization

  2. b

    The geometry of PCl5\mathrm{PCl_5} is trigonal bipyramidal

  3. c

    PCl5\mathrm{PCl_5} has two axial bonds stronger than three equatorial bonds

  4. d

    The three equatorial bonds of PCl5\mathrm{PCl_5} lie in a plane

Correct Answerc

PCl5\mathrm{PCl_5} has two axial bonds stronger than three equatorial bonds

Detailed Solution

🧠 In \cePCl5\ce{PCl5} (trigonal bipyramidal), there are two types of bonds: 3 equatorial (shorter, ~202 pm) and 2 axial (longer, ~214 pm). The question asks for the incorrect statement.

(a) P uses sp³d hybridisation → Correct

(b) Trigonal bipyramidal geometry → Correct

(c) "Axial bonds stronger than equatorial bonds" → Incorrect ✗. Axial P–Cl bonds are longer and weaker than equatorial bonds. Equatorial bonds experience only 2 axial neighbours at 90°, while axial bonds experience 3 equatorial neighbours at 90°, increasing LP-type repulsions and weakening the axial bond. Shorter = stronger.

(d) Three equatorial bonds lie in a plane → Correct

Answer: (c)\boxed{\text{Answer: (c)}}

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Identify the incorrect statement for PCl5 from the following: (JEE Main 2022) | Canvas Classes