JEE Main · 2019 · Shift-IIeasyCK-083

For a reaction scheme A k1 B k2 C, if the net rate of formation of B is set to be zero then the concentration of B is…

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

For a reaction scheme Ak1Bk2C\mathrm{A} \xrightarrow{k_1} \mathrm{B} \xrightarrow{k_2} \mathrm{C}, if the net rate of formation of B is set to be zero then the concentration of B is given by:

Options
  1. a

    (k1+k2)[A](k_1 + k_2)[\mathrm{A}]

  2. b

    k1k2[A]k_1 k_2[\mathrm{A}]

  3. c

    (k1k2)[A]\left(\frac{k_1}{k_2}\right)[\mathrm{A}]

  4. d

    (k1k2)[A](k_1 - k_2)[\mathrm{A}]

Correct Answerc

(k1k2)[A]\left(\frac{k_1}{k_2}\right)[\mathrm{A}]

Detailed Solution

Net rate of formation of B: d[B]dt=k1[A]k2[B]=0\frac{d[\mathrm{B}]}{dt} = k_1[\mathrm{A}] - k_2[\mathrm{B}] = 0 [B]=k1k2[A][\mathrm{B}] = \frac{k_1}{k_2}[\mathrm{A}]

Answer: Option (3)

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For a reaction scheme A k1 B k2 C, if the net rate of formation of B is set to be zero then the… (JEE Main 2019) | Canvas Classes