JEE Main · 2020 · Shift-IImediumCK-007

The graph which represents the following reaction is: {(C_6H_5)_3C{-}Cl} {{OH^-/Pyridine}} {(C_6H_5)_3C{-}OH}

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

The graph which represents the following reaction is: (C6H5)3CClOH/Pyridine(C6H5)3COH\mathrm{(C_6H_5)_3C{-}Cl} \xrightarrow{\mathrm{OH^-/Pyridine}} \mathrm{(C_6H_5)_3C{-}OH} image

Options
  1. a

    Option 1

  2. b

    Option 2

  3. c

    Option 3

  4. d

    Option 4

Correct Answerc

Option 3

Detailed Solution

(C6H5)3CCl\mathrm{(C_6H_5)_3CCl} undergoes SN1 reaction (unimolecular nucleophilic substitution) because the triphenylmethyl carbocation is highly stabilised by resonance.

In SN1: Rate = k[(C6H5)3CCl]k[\mathrm{(C_6H_5)_3CCl}]first order, depends only on the substrate, not on OH\mathrm{OH^-}.

The graph showing rate vs [OH][\mathrm{OH^-}] should be a horizontal line (rate independent of [OH][\mathrm{OH^-}]), while rate vs [substrate][\mathrm{substrate}] should be a straight line through origin.

Answer: Option (3)

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The graph which represents the following reaction is: {(C_6H_5)_3C{-}Cl} {{OH^-/Pyridine}}… (JEE Main 2020) | Canvas Classes