JEE Main · 2020 · Shift-ImediumCK-105

The rate of a certain biochemical reaction at physiological temperature (T) occurs 106 times faster with enzyme than…

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

The rate of a certain biochemical reaction at physiological temperature (T) occurs 10610^6 times faster with enzyme than without. The change in the activation energy upon adding enzyme is:

Options
  1. a

    6(2.303)RT-6(2.303)RT

  2. b

    6RT-6RT

  3. c

    +6(2.303)RT+6(2.303)RT

  4. d

    +6RT+6RT

Correct Answera

6(2.303)RT-6(2.303)RT

Detailed Solution

kenzymekno enzyme=106\frac{k_{\text{enzyme}}}{k_{\text{no enzyme}}} = 10^6

kenzymekno enzyme=e(Ea,uncatEa,cat)/RT=106\frac{k_{\text{enzyme}}}{k_{\text{no enzyme}}} = e^{(E_{a,\text{uncat}} - E_{a,\text{cat}})/RT} = 10^6

ΔEaRT=ln106=6ln10=6×2.303\frac{\Delta E_a}{RT} = \ln 10^6 = 6\ln 10 = 6 \times 2.303

ΔEa=Ea,catEa,uncat=6(2.303)RT\Delta E_a = E_{a,\text{cat}} - E_{a,\text{uncat}} = -6(2.303)RT

(Negative because enzyme lowers activation energy)

Answer: Option (1) — 6(2.303)RT-6(2.303)RT

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Chemical Kinetics) inside The Crucible, our adaptive practice platform.