JEE Main · 2025 · Shift-IhardCK-131

The reaction A2 + B2 - 2AB follows the mechanism: The overall order of the reaction is:

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

The reaction \ceA2+B2>2AB\ce{A2 + B2 -> 2AB} follows the mechanism: image The overall order of the reaction is:

Options
  1. a

    1.5

  2. b

    3

  3. c

    2.5

  4. d

    2

Correct Answera

1.5

Detailed Solution

Step 1 — Rate from slow step

Rate =k2[\ceA][\ceB2]= k_2[\ce{A}][\ce{B2}]

Step 2 — Eliminate intermediate [A] using pre-equilibrium

Keq=[\ceA]2[\ceA2]K_{eq} = \frac{[\ce{A}]^2}{[\ce{A2}]}[\ceA]=Keq[\ceA2]1/2[\ce{A}] = \sqrt{K_{eq}} \cdot [\ce{A2}]^{1/2}

Step 3 — Substitute

Rate =k2Keq[\ceA2]1/2[\ceB2]1= k_2 \sqrt{K_{eq}} \cdot [\ce{A2}]^{1/2} [\ce{B2}]^1

Overall order =12+1=1.5= \frac{1}{2} + 1 = 1.5Option (a)

Key Points to Remember:

  • Rate = slow step rate; eliminate intermediates via equilibrium
  • [\ceA][\ceA2]1/2[\ce{A}] \propto [\ce{A2}]^{1/2} from fast equilibrium
  • Overall order = 1/2 + 1 = 1.5

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Chemical Kinetics) inside The Crucible, our adaptive practice platform.

The reaction A2 + B2 - 2AB follows the mechanism: The overall order of the reaction is: (JEE Main 2025) | Canvas Classes