JEE Main · 2020 · Shift-ImediumPERI-043

The statement(s) that are correct about the species O2-, F-, Na+ and Mg2+: (A) All are isoelectronic (B) All have the…

Classification of Elements & Periodicity · Class 11 · JEE Main Previous Year Question

Question

The statement(s) that are correct about the species \ceO2\ce{O^{2-}}, \ceF\ce{F^-}, \ceNa+\ce{Na^+} and \ceMg2+\ce{Mg^{2+}}:

(A) All are isoelectronic (B) All have the same nuclear charge (C) \ceO2\ce{O^{2-}} has the largest ionic radii (D) \ceMg2+\ce{Mg^{2+}} has the smallest ionic radii

Options
  1. a

    (B), (C) and (D) only

  2. b

    (C) and (D) only

  3. c

    (A), (C) and (D) only

  4. d

    (A), (B), (C) and (D)

Correct Answerc

(A), (C) and (D) only

Detailed Solution

🧠 Isoelectronic = same electrons. It does NOT mean same nuclear charge — that is the catch in statement (B) \ceO2\ce{O^{2-}}, \ceF\ce{F^-}, \ceNa+\ce{Na^+}, \ceMg2+\ce{Mg^{2+}} each have 10 electrons but very different proton counts (8, 9, 11, 12). The four statements test whether you grasp this distinction.

🗺️ Check each statement (A) All are isoelectronic — count electrons: 8+28+2, 9+19+1, 11111-1, 12212-2, all give 10. True. (B) All have the same nuclear charge — Z values are 8, 9, 11, 12. All different. False. (C) \ceO2\ce{O^{2-}} has the largest ionic radius — lowest Z (8) means weakest pull on the same 10 electrons → biggest. True. (D) \ceMg2+\ce{Mg^{2+}} has the smallest ionic radius — highest Z (12) means strongest pull → smallest. True.

Correct statements: A, C, D.

⚠️ The trap Statement (B) is the classic confusion. Isoelectronic literally means "same electrons", not "same charge". Many students assume isoelectronic species share everything — same size, same charge, same Z. They share only the electron count. Everything else can differ.

Answer: (c)\boxed{\text{Answer: (c)}}

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