JEE Main · 2024easyCORD-188

In which one of the following metal carbonyls, CO forms a bridge between metal atoms?

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

In which one of the following metal carbonyls, CO forms a bridge between metal atoms?

Options
  1. a

    [Co2(CO)8][\mathrm{Co_2(CO)_8}]

  2. b

    [Mn2(CO)10][\mathrm{Mn_2(CO)_{10}}]

  3. c

    [Os3(CO)12][\mathrm{Os_3(CO)_{12}}]

  4. d

    [Ru3(CO)12][\mathrm{Ru_3(CO)_{12}}]

Correct Answera

[Co2(CO)8][\mathrm{Co_2(CO)_8}]

Detailed Solution

🧠 Bridging vs Terminal CO

A bridging CO (μ-CO) connects two metal centres simultaneously: M ⁣ ⁣C( ⁣= ⁣O) ⁣ ⁣M\mathrm{M\!-\!C(\!=\!O)\!-\!M} with both M–C bonds.

Walk the four candidates:

| Carbonyl | Metals | Bridging COs | Notes | |---|---|---|---| | Co2(CO)8\mathrm{Co_2(CO)_8} | 2 Co | 2 ✓ | Solid-state structure: 2 μ-CO + 6 terminal + Co–Co | | Mn2(CO)10\mathrm{Mn_2(CO)_{10}} | 2 Mn | 0 | All 10 CO terminal; only Mn–Mn metal bond | | Os3(CO)12\mathrm{Os_3(CO)_{12}} | 3 Os | 0 | All 12 CO terminal (4 per Os); 3 Os–Os bonds | | Ru3(CO)12\mathrm{Ru_3(CO)_{12}} | 3 Ru | 0 | All 12 CO terminal; 3 Ru–Ru bonds |

Only Co2(CO)8\mathrm{Co_2(CO)_8} shows bridging CO.

🗺️ Why Mn₂(CO)₁₀ Has No Bridges

In Mn₂(CO)₁₀, each Mn satisfies 18-electron rule with 5 terminal CO + 1 Mn–Mn bond: 7+5(2)+1=187 + 5(2) + 1 = 18 \checkmark

Adding bridging COs would over-count electrons — so the symmetry-allowed terminal-only structure is preferred.

In Co₂(CO)₈, the alternative all-terminal structure exists in solution but the solid-state form has the bridging arrangement to satisfy crystal packing + electron count.

Bridging vs Terminal as a Function of M–M Distance

Bridging CO is favoured when M–M distance allows: in Co–Co (2.49 Å), the metals are close enough for 2 bridging COs to fit. In Mn–Mn (longer, ~2.93 Å) or Os–Os/Ru–Ru triangles, the geometry doesn't favour bridging.

⚠️ Solution vs Solid Structures

Many di- and trinuclear carbonyls have multiple isomeric forms differing by bridge count. Always specify "solid-state structure" when comparing — the solution form may differ.

Answer: (1) [Co2(CO)8]\boxed{\text{Answer: (1) } [\mathrm{Co_2(CO)_8}]}

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