The correct increasing order of stability of the complexes based on o value is: (I) [Mn(CN)6]3- (II) [Co(CN)6]4- (III)…
Coordination Compounds · Class 12 · JEE Main Previous Year Question
The correct increasing order of stability of the complexes based on value is:
(I) (II) (III) (IV)
- a
- b
- c✓
- d
🧠 Stability ∝ CFSE ∝ Δₒ
Stability scales with CFSE. CFSE depends on:
- Metal d-configuration.
- Ligand field strength (here all CN⁻ — but varies with metal OS).
- Spin state.
Higher metal oxidation state → higher charge → larger .
🗺️ Compute CFSE for Each
| # | Complex | Metal/d-config | LS Configuration (CN⁻ strong field) | CFSE (×) | |---|---|---|---|---| | (I) | | Mn(III) d⁴ LS | | | | (II) | | Co(II) d⁷ LS | | | | (III) | | Fe(II) d⁶ LS | | | | (IV) | | Fe(III) d⁵ LS | | |
🗺️ Order by CFSE Magnitude
Less stable → more stable:
So increasing stability: I < II < IV < III.
⚡ CFSE Order Cheat (for LS oct)
| d-electrons | CFSE (×) | |---|---| | d⁴ LS | | | d⁵ LS | | | d⁶ LS | ← maximum | | d⁷ LS | | | d⁸ LS | |
⚠️ Δₒ Differences Between OS States
Higher M oxidation state ⇒ larger for same metal+ligand. So (Fe³⁺) has bigger than (Fe²⁺) — but that's per-Δₒ, and CFSE in Δₒ units favours d⁶ over d⁵.
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