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Which of the following are examples of double salt? (A) FeSO4(NH4)2SO4 6H2O (B) CuSO4 4NH3 H2O (C) K2SO4 Al2(SO4)3…

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

Which of the following are examples of double salt? (A) FeSO4(NH4)2SO46H2O\mathrm{FeSO_4\cdot(NH_4)_2SO_4\cdot 6H_2O} (B) CuSO44NH3H2O\mathrm{CuSO_4\cdot 4NH_3\cdot H_2O} (C) K2SO4Al2(SO4)324H2O\mathrm{K_2SO_4\cdot Al_2(SO_4)_3\cdot 24H_2O} (D) Fe(CN)24KCN\mathrm{Fe(CN)_2\cdot 4KCN}

Options
  1. a

    A and C only

  2. b

    A and B only

  3. c

    A, B and D only

  4. d

    B and D only

Correct Answera

A and C only

Detailed Solution

🧠 The Aqueous Dissociation Test

Double salt vs coordination compound is settled by one question: when you dissolve it in water, does the metal-ligand bond survive?

  • Double salt — fully dissociates into all constituent simple ions. No coordination sphere persists.
  • Coordination compound — the complex ion holds together; the metal stays bound to its ligands.

Mohr's salt and potash alum are the canonical double salts; both fall apart in water. Tetraamminecopper sulfate and potassium ferrocyanide hold their coordination spheres firmly — they're complexes.

🗺️ Tag Each Compound

(A) FeSO4(NH4)2SO46H2O\mathrm{FeSO_4 \cdot (NH_4)_2SO_4 \cdot 6H_2O}Mohr's salt. In water → Fe2+\mathrm{Fe^{2+}}, NH4+\mathrm{NH_4^+}, SO42\mathrm{SO_4^{2-}}. Double salt ✓ (B) CuSO44NH3H2O\mathrm{CuSO_4 \cdot 4NH_3 \cdot H_2O} — actually [Cu(NH3)4]SO4H2O[\mathrm{Cu(NH_3)_4}]\mathrm{SO_4 \cdot H_2O}. The deep blue [Cu(NH3)4]2+[\mathrm{Cu(NH_3)_4}]^{2+} ion survives — coordination compound. (C) K2SO4Al2(SO4)324H2O\mathrm{K_2SO_4 \cdot Al_2(SO_4)_3 \cdot 24H_2O}potash alum. In water → K+\mathrm{K^+}, Al3+\mathrm{Al^{3+}}, SO42\mathrm{SO_4^{2-}}. Double salt ✓ (D) Fe(CN)24KCN\mathrm{Fe(CN)_2 \cdot 4KCN} — really K4[Fe(CN)6]\mathrm{K_4[Fe(CN)_6]}, potassium ferrocyanide. The [Fe(CN)6]4[\mathrm{Fe(CN)_6}]^{4-} ion is very stable — coordination compound.

So A and C only.

The "Colour Test"

If the dissolved solution gives the characteristic colour of the free metal ion (pale blue Cu2+\mathrm{Cu^{2+}}, pale green Fe2+\mathrm{Fe^{2+}}), the bond broke — it was a double salt. If the colour is something new (deep blue tetraammine, yellow ferrocyanide), a coordination sphere is still intact. Real lab habit, fast on paper.

⚠️ Hydrate Water Counts as a Salt Component

Don't confuse "nH2O\cdot \, n\mathrm{H_2O}" (water of crystallisation, present in both double salts and many complex salts) with the deciding factor. Whether a compound is a double salt is decided by what dissociates in solution, not by how many waters it carries in the solid.

Answer: (1) A and C only\boxed{\text{Answer: (1) A and C only}}

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