JEE Main · 2023 · Shift-IeasyDNF-059

The correct order of basicity of oxides of vanadium is:

d & f-Block Elements · Class 12 · JEE Main Previous Year Question

Question

The correct order of basicity of oxides of vanadium is:

Options
  1. a

    V2O3>V2O4>V2O5\text{V}_2\text{O}_3 > \text{V}_2\text{O}_4 > \text{V}_2\text{O}_5

  2. b

    V2O3>V2O5>V2O4\text{V}_2\text{O}_3 > \text{V}_2\text{O}_5 > \text{V}_2\text{O}_4

  3. c

    V2O5>V2O4>V2O3\text{V}_2\text{O}_5 > \text{V}_2\text{O}_4 > \text{V}_2\text{O}_3

  4. d

    V2O4>V2O3>V2O5\text{V}_2\text{O}_4 > \text{V}_2\text{O}_3 > \text{V}_2\text{O}_5

Correct Answera

V2O3>V2O4>V2O5\text{V}_2\text{O}_3 > \text{V}_2\text{O}_4 > \text{V}_2\text{O}_5

Detailed Solution

Concept: Basicity of metal oxides decreases as oxidation state increases

| Oxide | V O.S. | Nature | |-------|--------|--------| | V2O3\text{V}_2\text{O}_3 | +3 | Basic (most basic) | | V2O4\text{V}_2\text{O}_4 | +4 | Amphoteric | | V2O5\text{V}_2\text{O}_5 | +5 | Acidic (least basic) |

Rule: As oxidation state increases, the metal-oxygen bond becomes more covalent → oxide becomes more acidic (less basic).

Decreasing basicity: V2O3(+3)>V2O4(+4)>V2O5(+5)\text{V}_2\text{O}_3 (+3) > \text{V}_2\text{O}_4 (+4) > \text{V}_2\text{O}_5 (+5)

Answer: Option (1)

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from d & f-Block Elements) inside The Crucible, our adaptive practice platform.

The correct order of basicity of oxides of vanadium is: (JEE Main 2023) | Canvas Classes