JEE Main · 2022 · Shift-ImediumEC-094

Match List-I with List-II. List-I | | Reaction | |---|---| | A | Cd(s) + 2Ni(OH)3(s) CdO(s) + 2Ni(OH)2(s) + H2O(l) | |…

Electrochemistry · Class 12 · JEE Main Previous Year Question

Question

Match List-I with List-II.

List-I

| | Reaction | |---|---| | A | Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)\mathrm{Cd(s) + 2Ni(OH)_3(s) \rightarrow CdO(s) + 2Ni(OH)_2(s) + H_2O(l)} | | B | Zn(Hg)+HgO(s)→ZnO(s)+Hg(l)\mathrm{Zn(Hg) + HgO(s) \rightarrow ZnO(s) + Hg(l)} | | C | 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq)\mathrm{2PbSO_4(s) + 2H_2O(l) \rightarrow Pb(s) + PbO_2(s) + 2H_2SO_4(aq)} | | D | 2H2(g)+O2(g)→2H2O(l)\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(l)} |

List-II: I. Primary battery, II. Discharging of secondary battery, III. Fuel cell, IV. Charging of secondary battery

Choose the correct answer from the options given below:

Options
  1. a

    A-I, B-II, C-III, D-IV

  2. b

    A-IV, B-I, C-IV, D-III

  3. c

    A-II, B-I, C-IV, D-III

    ✓
  4. d

    A-II, B-I, C-III, D-IV

Correct Answerc

A-II, B-I, C-IV, D-III

Detailed Solution

Strategy: Match industrial battery reactions with their specific classifications (Primary, Secondary, Fuel Cell) and state (Charging vs. Discharging).

Matching Analysis:

  • (A) \ceCd+Ni(OH)3\ce{Cd + Ni(OH)_3}: This is the spontaneous discharge of a Nickel-Cadmium battery (Secondary). →\rightarrow II
  • (B) \ceZn(Hg)+HgO\ce{Zn(Hg) + HgO}: Net reaction of a Mercury cell (Primary battery). →\rightarrow I
  • (C) \cePbSO4+H2O→Pb+PbO2\ce{PbSO4 + H2O \rightarrow Pb + PbO2}: This is the non-spontaneous charging of a Lead-Acid battery (Secondary). →\rightarrow IV
  • (D) \ceH2+O2→H2O\ce{H2 + O2 \rightarrow H2O}: Net reaction of an \ceH2−O2\ce{H2-O2} fuel cell. →\rightarrow III

Match: A-II, B-I, C-IV, D-III.

Answer:(c)A−II,B−I,C−IV,D−III\boxed{{Answer: (c) A-II, B-I, C-IV, D-III}}

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