JEE Main · 2024 · Shift-IIeasyEC-093

The reaction: {1}{2}{H_{2(g)}} + {AgCl_{(s)}} {H^+_{(aq)}} + {Cl^-_{(aq)}} + {Ag_{(s)}} occurs in which of the…

Electrochemistry · Class 12 · JEE Main Previous Year Question

Question

The reaction: 12H2(g)+AgCl(s)→H(aq)++Cl(aq)−+Ag(s)\frac{1}{2}\mathrm{H_{2(g)}} + \mathrm{AgCl_{(s)}} \rightarrow \mathrm{H^+_{(aq)}} + \mathrm{Cl^-_{(aq)}} + \mathrm{Ag_{(s)}} occurs in which of the following galvanic cell:

Options
  1. a

    Ag∣AgCl(s)∣KCl(soln.)∣AgNO3(aq.)∣Ag\mathrm{Ag|AgCl_{(s)}|KCl_{(soln.)}|AgNO_{3(aq.)}|Ag}

  2. b

    Pt∣H2(g)∣HCl(soln.)∣AgCl(s)∣Ag\mathrm{Pt|H_{2(g)}|HCl_{(soln.)}|AgCl_{(s)}|Ag}

    ✓
  3. c

    Pt∣H2(g)∣KCl(soln.)∣AgCl(s)∣Ag\mathrm{Pt|H_{2(g)}|KCl_{(soln.)}|AgCl_{(s)}|Ag}

  4. d

    Pt∣H2(g)∣HCl(soln.)∣AgNO3(aq.)∣Ag\mathrm{Pt|H_{2(g)}|HCl_{(soln.)}|AgNO_{3(aq.)}|Ag}

Correct Answerb

Pt∣H2(g)∣HCl(soln.)∣AgCl(s)∣Ag\mathrm{Pt|H_{2(g)}|HCl_{(soln.)}|AgCl_{(s)}|Ag}

Detailed Solution

Strategy: Match the balan\ced redox reaction to the standard IUPAC cell representation (Anode∣Electrolyte∣∣Electrolyte∣CathodeAnode | Electrolyte || Electrolyte | Cathode).

Analysis of the reaction: \ce12H2(g)+AgCl(s)→H+(aq)+Cl−(aq)+Ag(s)\ce{\frac{1}{2}H_2(g) + AgCl(s) \rightarrow H^+(aq) + Cl^-(aq) + Ag(s)}

  1. Oxidation: \ce12H2→H++e−\ce{\frac{1}{2}H_2 \rightarrow H^+ + e^-}. This requires a Platinum electrode (\cePt∣H2∣H+\ce{Pt | H2 | H^+}). Sin\ce \ceCl−\ce{Cl^-} is also in solution, \ceHCl\ce{HCl} is the common electrolyte.
  2. Reduction: \ceAgCl(s)+e−→Ag(s)+Cl−\ce{AgCl(s) + e^- \rightarrow Ag(s) + Cl^-}. This is the silver-silver chloride electrode (\ceCl−∣AgCl∣Ag\ce{Cl^- | AgCl | Ag}).

Representation: \cePt∣H2∣HCl(aq)∣AgCl(s)∣Ag\ce{Pt | H2 | HCl(aq) | AgCl(s) | Ag}

Answer: (b) \cePt∣H2(g)∣HCl(soln.)∣AgCl(s)∣Ag\boxed{\text{Answer: (b) } \ce{Pt|H_{2(g)}|HCl_{(soln.)}|AgCl_{(s)}|Ag}}

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