Choose the halogen which is most reactive towards SN1 reaction in the given compounds (A, B, C & D):
Haloalkanes & Haloarenes · Class 12 · JEE Main Previous Year Question
Choose the halogen which is most reactive towards reaction in the given compounds (A, B, C & D):
- a
A-Br(a); B-I(a); C-Br(b); D-Br(a)
- b
A-Br(a); B-I(a); C-Br(b); D-Br(a)
- c
A-Br(a); B-I(a); C-Br(b); D-Br(a)
- d✓
A-Br(a); C-Br(b); C-Br(b); D-Br(a)
A-Br(a); C-Br(b); C-Br(b); D-Br(a)
Step 1: Understand reactivity
reactivity depends on carbocation stability:
Stability order:
- Benzylic > Allylic > 3° > 2° > 1° > Methyl
- Resonance stabilization is key
Step 2: Analyze each position
Position A: Br on benzene ring (aryl bromide)
- Aryl halides do not undergo
- Aryl carbocation extremely unstable
- Very low reactivity ✗
Position B: I on allylic position
- Allylic carbocation (resonance stabilized)
- I is best leaving group
- High reactivity ✓✓
Position C: Br on bridgehead (bicyclic system)
- Bridgehead carbocations are very unstable (Bredt's rule)
- Cannot adopt planar geometry
- Very low reactivity ✗
Position D: Br on benzylic position
- Benzylic carbocation (resonance with benzene)
- High reactivity ✓
Step 3: Rank reactivity
Most reactive for :
B (allylic I) ≈ D (benzylic Br) >> A (aryl Br) ≈ C (bridgehead Br)
Between B and D:
- Both have resonance stabilization
- I is better leaving group than Br
- B is most reactive
Answer: (b)
Key Points:
- Allylic/benzylic positions: Highly reactive in (resonance)
- Aryl halides: Do not undergo (unstable carbocation)
- Bridgehead halides: Do not undergo (Bredt's rule)
- Leaving group ability: I > Br > Cl > F
- Resonance stabilization: Delocalizes positive charge over multiple atoms
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