JEE Main · 2023 · Shift-IhardHALO-071

For the reaction: The correct statement from the following is:

Haloalkanes & Haloarenes · Class 12 · JEE Main Previous Year Question

Question

For the reaction: image The correct statement from the following is:

Options
  1. a

    The transition state formed in the above reaction is less polar than the localised anion.

  2. b

    The reaction can occur in acetic acid also.

  3. c

    The solvent used in the reaction solvates the ions formed in rate determining step.

  4. d

    Br can act as competing nucleophile.

Correct Answera

The transition state formed in the above reaction is less polar than the localised anion.

Detailed Solution

Step 1: Identify the reaction

This appears to be an iodide exchange reaction (Finkelstein-type):

\ceRCH2I+I>RCH2I+I\ce{R-CH2-I + I- -> R-CH2-I + I-}

Wait, this is the same compound on both sides. Let me reconsider.

Actually, this might be showing isotopic exchange or the mechanism of SN2S_N2 with iodide.

Mechanism: SN2S_N2

\ceI+RCH2I>[ICH2RI]>ICH2R+I\ce{I- + R-CH2-I -> [I---CH2R---I]^- -> I-CH2R + I-}

Step 2: Analyze the transition state

SN2S_N2 transition state:

  • Trigonal bipyramidal geometry
  • Partial bonds to both incoming and leaving I
  • Negative charge delocalized over two iodine atoms

Localized anion (reactant):

  • Free \ceI\ce{I-} ion
  • Full negative charge on single iodine
  • More polar (concentrated charge)

Transition state:

  • Charge spread over larger area (two I atoms)
  • Less polar than localized anion

Statement (a) is TRUE

Step 3: Evaluate other statements

(b) "The reaction can occur in acetic acid also."

  • Acetic acid is polar protic solvent
  • Strongly solvates anions (H-bonding)
  • SN2S_N2 is slower in protic solvents
  • Acetone (polar aprotic) is much better
  • Statement is misleading/false ✗

(c) "The solvent used in the reaction solvates the ions formed in rate determining step."

  • Acetone is polar aprotic
  • Does NOT strongly solvate anions (no H-bonding)
  • This is why it's good for SN2S_N2 (nucleophile is "naked")
  • Statement is FALSE ✗

(d) "Br can act as competing nucleophile."

  • Not relevant to this specific reaction
  • No Br mentioned in the reaction
  • Statement is irrelevant/false ✗

Answer: (a)

Key Concepts:

SN2S_N2 Transition State:

  • Charge delocalization
  • Less polar than separated ions
  • Stabilized by charge dispersal

Solvent Effects:

| Solvent Type | Examples | Effect on SN2S_N2 | |--------------|----------|------------------| | Polar aprotic | Acetone, DMSO, DMF | Fast (doesn't solvate Nu⁻) | | Polar protic | H₂O, ROH, RCOOH | Slow (solvates Nu⁻) |

Finkelstein Reaction:

  • Halogen exchange using NaI in acetone
  • Driven by precipitation of NaCl/NaBr
  • SN2S_N2 mechanism

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