JEE Main · 2019 · Shift-IhardIEQ-025

Consider the following statements: (a) The pH of a mixture containing 400 mL of 0.1 M H2SO4 and 400 mL of 0.1 M NaOH…

Ionic Equilibrium · Class 11 · JEE Main Previous Year Question

Question

Consider the following statements:

(a) The pH of a mixture containing 400 mL of 0.1 M H2SO4\mathrm{H_2SO_4} and 400 mL of 0.1 M NaOH will be approximately 1.3. (b) Ionic product of water is temperature dependent. (c) A monobasic acid with Ka=105K_a = 10^{-5} has pH = 5. The degree of dissociation of this acid is 50%. (d) The Le Chatelier's principle is not applicable to common-ion effect.

The correct statements are:

Options
  1. a

    (b) and (c)

  2. b

    (a), (b) and (d)

  3. c

    (a) and (b)

  4. d

    (a), (b) and (c)

Correct Answerd

(a), (b) and (c)

Detailed Solution

Step 1 — Evaluate each statement:

(a) pH of mixture of 400 mL 0.1M H2SO4\mathrm{H_2SO_4} + 400 mL 0.1M NaOH: Moles H+\mathrm{H^+} from H2SO4\mathrm{H_2SO_4} = 2×0.1×0.4=0.082 \times 0.1 \times 0.4 = 0.08 mol Moles OH\mathrm{OH^-} from NaOH = 0.1×0.4=0.040.1 \times 0.4 = 0.04 mol Excess H+\mathrm{H^+} = 0.080.04=0.040.08 - 0.04 = 0.04 mol in 800 mL [H+]=0.04/0.8=0.05[\mathrm{H^+}] = 0.04/0.8 = 0.05 M \rightarrow pH = log(0.05)=1.3-\log(0.05) = 1.3Correct

(b) KwK_w is temperature dependent:CorrectKwK_w increases with temperature.

(c) Ka=105K_a = 10^{-5}, pH = 5, degree of dissociation = 50%: If pH = 5, [H+]=105[\mathrm{H^+}] = 10^{-5} M Ka=α2C1αK_a = \frac{\alpha^2 C}{1-\alpha}; if α=0.5\alpha = 0.5: Ka=0.25C0.5=0.5CK_a = \frac{0.25C}{0.5} = 0.5C For Ka=105K_a = 10^{-5}: C=2×105C = 2 \times 10^{-5} M, [H+]=αC=105[\mathrm{H^+}] = \alpha C = 10^{-5}Correct

(d) Le Chatelier's principle NOT applicable to common-ion effect:Incorrect — Le Chatelier's principle IS the basis for the common-ion effect.

Correct: a, b, c

Answer: Option (4) — (a), (b) and (c)

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