JEE Main · 2025 · Shift-IeasyMOLE-215

Among 10-9 g (each) of the following elements, which one will have the highest number of atoms? Element: Pb, Po, Pr and…

Some Basic Concepts (Mole Concept) · Class 11 · JEE Main Previous Year Question

Question

Among 10910^{-9} g (each) of the following elements, which one will have the highest number of atoms? Element: Pb, Po, Pr and Pt

Options
  1. a

    Po

  2. b

    Pr

  3. c

    Pb

  4. d

    Pt

Correct Answerb

Pr

Detailed Solution

🧠 Same mass — lighter atom wins If you fix the mass at 109g10^{-9}\,\text{g}, the element with the smallest atomic mass has the most atoms. It is n=m/Mn = m/M — small MM means big nn.

🗺️ Compare the four

  • Pb: 207\sim 207
  • Po: 209\sim 209
  • Pr: 141\sim 141
  • Pt: 195\sim 195

Praseodymium (Pr) is by far the lightest in this group. So Pr has the highest atom count.

⚠️ Common mistake Many students pick Pt or Pb because the names sound "heavy and metallic". The trick is: same mass, lighter atom = more atoms.

Answer: (b)\boxed{\text{Answer: (b)}}

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