JEE Main · 2020 · Shift-IImediumMOLE-150

The strengths of 5.6 volume hydrogen peroxide (density 1\,g/mL) in terms of mass percentage and molarity (M)…

Some Basic Concepts (Mole Concept) · Class 11 · JEE Main Previous Year Question

Question

The strengths of 5.65.6 volume hydrogen peroxide (density 1 g/mL1\,\text{g/mL}) in terms of mass percentage and molarity (M) respectively are: (Molar mass of \ceH2O2=34 g/mol\ce{H2O2}=34\,\text{g/mol})

Options
  1. a

    1.71.7 and 0.50.5

    ✓
  2. b

    0.850.85 and 0.250.25

  3. c

    1.71.7 and 0.250.25

  4. d

    0.850.85 and 0.50.5

Correct Answera

1.71.7 and 0.50.5

Detailed Solution

🧠 "5.65.6 volume" is a marker for 0.5 M0.5\,\text{M} Volume strength =11.2×M= 11.2 \times M (where MM is molarity of \ceH2O2\ce{H2O2}). So 5.6=11.2×M5.6 = 11.2 \times M gives M=0.5M = 0.5. Since the density is 1 g/mL1\,\text{g/mL}, 1 L1\,\text{L} weighs 1000 g1000\,\text{g}, and the solute mass is 0.5×34=17 g0.5 \times 34 = 17\,\text{g}.

🗺️ Two steps Molarity: M=5.6/11.2=0.5 MM = 5.6/11.2 = 0.5\,\text{M}. Mass percentage: (17/1000)×100=1.7%(17 / 1000) \times 100 = 1.7\%.

So the pair is (1.7%, 0.5 M)(1.7\%,\ 0.5\,\text{M}).

⚡ Speed scan Spot the pattern: 11.2×M11.2 \times M formula gives molarity, and 34M/1034M / 10 gives mass percentage when density is 11. Locks onto option (a).

Answer: (a)\boxed{\text{Answer: (a)}}

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