JEE Main · 2022 · Shift-IhardPB12-116

Consider the following reaction: {2HSO_4^-(aq) {{(1) Electrolysis, (2) Hydrolysis}} 2HSO_4^- + 2H^+ + A} The dihedral…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Consider the following reaction:

2HSO4−(aq)→(1) Electrolysis, (2) Hydrolysis2HSO4−+2H++A\mathrm{2HSO_4^-(aq) \xrightarrow{\text{(1) Electrolysis, (2) Hydrolysis}} 2HSO_4^- + 2H^+ + A}

The dihedral angle in product A in its solid phase at 110 K is

Options
  1. a

    104°104°

  2. b

    111.5°111.5°

  3. c

    90.2°90.2°

    ✓
  4. d

    111.0°111.0°

Correct Answerc

90.2°90.2°

Detailed Solution

Strategy: Identify product A and recall its structural parameters in different phases.

Step 1: Reaction Identification Electrolysis of acidified sulphate (\ceHSO4−)(\ce{HSO4^-}) followed by hydrolysis yields Hydrogen peroxide (\ceH2O2)(\ce{H2O2}): \ce2HSO4−→electrolysisH2S2O8→hydrolysis2HSO4−+2H++H2O2\ce{2HSO4^- \xrightarrow{\text{electrolysis}} H2S2O8 \xrightarrow{\text{hydrolysis}} 2HSO4^- + 2H^+ + H2O2} Thus, A is \ceH2O2\ce{H2O2}.

Step 2: Structural Parameters \ceH2O2\ce{H2O2} has a non-planar "open book" structure.

  • In gas phase, the dihedral angle is ≈111.5°\approx 111.5\text{°}.
  • In solid phase (at low temperatures like 110 K110 \text{ K}), the dihedral angle decreases significantly due to hydrogen bonding to 90.2°90.2\text{°}.

Answer: (Option) [c] 90.2°\boxed{\text{Answer: (Option) [c] 90.2°}}

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Consider the following reaction: {2HSO_4^-(aq) {{(1) Electrolysis, (2) Hydrolysis}} 2HSO_4^- + 2H^+… (JEE Main 2022) | Canvas Classes