JEE Main · 2023 · Shift-IhardPB12-002

Match List I with List II | | List I (Oxide) | | List II (Type of bond) | |---|---|---|---| | A | N2O4 | I | 1\,N=O…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Match List I with List II

| | List I (Oxide) | | List II (Type of bond) | |---|---|---|---| | A | N2O4\mathrm{N_2O_4} | I | 1 N=O1\,\mathrm{N=O} bond | | B | NO2\mathrm{NO_2} | II | 1 N−O−N1\,\mathrm{N-O-N} bond | | C | N2O5\mathrm{N_2O_5} | III | 1 N−N1\,\mathrm{N-N} bond | | D | N2O\mathrm{N_2O} | IV | 1 N=N/N≡N1\,\mathrm{N=N/N\equiv N} bond |

Choose the correct answer from the options given below:

Options
  1. a

    A−III, B−I, C−II, D−IV\mathrm{A-III,\ B-I,\ C-II,\ D-IV}

    ✓
  2. b

    A−II, B−IV, C−III, D−I\mathrm{A-II,\ B-IV,\ C-III,\ D-I}

  3. c

    A−III, B−I, C−IV, D−II\mathrm{A-III,\ B-I,\ C-IV,\ D-II}

  4. d

    A−II, B−I, C−III, D−IV\mathrm{A-II,\ B-I,\ C-III,\ D-IV}

Correct Answera

A−III, B−I, C−II, D−IV\mathrm{A-III,\ B-I,\ C-II,\ D-IV}

Detailed Solution

Strategy: Identify the structures of nitrogen oxides to find the specific bonding patterns.

Step 1: Structure Analysis

  • \ceN2O4\ce{N2O4} contains a direct \ceN−N\ce{N-N} bond (A-III).
  • \ceNO2\ce{NO2} is a monomer with one \ceN=O\ce{N=O} double bond and one coordinate/single bond (B-I).
  • \ceN2O5\ce{N2O5} (gas) has an anhydride structure with an \ceN−O−N\ce{N-O-N} bridge (C-II).
  • \ceN2O\ce{N2O} (nitrous oxide) has a linear structure with \ceN≡N−O\ce{N\equiv N-O} or \ceN=N=O\ce{N=N=O} (D-IV).

Step 2: Conclusion Matching the list gives: (A)-(III), (B)-(I), (C)-(II), (D)-(IV).

Answer: (Option) [a] (A)-(III), (B)-(I), (C)-(II), (D)-(IV)\boxed{\text{Answer: (Option) [a] (A)-(III), (B)-(I), (C)-(II), (D)-(IV)}}

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