JEE Main · 2022 · Shift-IImediumPB12-016

White phosphorus reacts with thionyl chloride to give

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Options

a
$\mathrm{PCl_5}$ , $\mathrm{SO_2}$ and $\mathrm{S_2Cl_2}$
b
$\mathrm{PCl_3}$ , $\mathrm{SO_2}$ and $\mathrm{S_2Cl_2}$
✓
c
$\mathrm{PCl_3}$ , $\mathrm{SO_2}$ and $\mathrm{Cl_2}$
d
$\mathrm{PCl_5}$ , $\mathrm{SO_2}$ and $\mathrm{Cl_2}$

Correct Answerb

$\mathrm{PCl_3}$ , $\mathrm{SO_2}$ and $\mathrm{S_2Cl_2}$

Detailed Solution

Strategy: Use the chemical equation for the reaction of white phosphorus with chlorine-donating agents.

Step 1: Reaction Details Reaction with thionyl chloride $(\ce{SOCl2})$ yields phosphorus trichloride: $\ce{P4 + 8SOCl2 \to 4PCl3 + 4SO2 + 2S2Cl2}$

Step 2: Comparison Note that reaction with sulfuryl chloride $(\ce{SO2Cl2})$ yields $\ce{PCl5}$ . Since thionyl chloride is used here, $\ce{PCl3}$ is the primary product.

$\boxed{\text{Answer: (Option) [b] $\ce{PCl3, SO2, S_2Cl2}$}}$

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