JEE Main · 2019 · Shift-IImediumSOL-119

For the solution of the gases w, x, y and z in water at 298 K, the Henry's law constants (KH) are 0.5, 2, 35 and 40…

Solutions · Class 12 · JEE Main Previous Year Question

Question

For the solution of the gases w, x, y and z in water at 298 K, the Henry's law constants (KHK_H) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is:

Options
  1. a

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  2. b

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  3. c

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  4. d

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Correct Answera

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Detailed Solution

Strategy:\n> According to Henry's Law p=KHxp = K_H \cdot x, a plot of partial pressure (pp) vs mole fraction (xx) is a straight line with slope KHK_H. Compare the values of KHK_H to determine the relative steepness of the lines for different gases.\n\nStep 1: Sort by slope (KHK_H)\n- w=0.5w = 0.5 (Lowest slope, most shallow)\n- x=2x = 2\n- y=35y = 35\n- z=40z = 40 (Highest slope, steepest line)\n\nStep 2: Select the correct graph\nGraph (1) correctly shows the slopes increasing in the sequence w < x < y < z. Note that for a given pressure, ww will be the most soluble (highest xx) while zz is the least.\n\ntextAnswer:(1)\boxed{\\text{Answer: (1)}}

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For the solution of the gases w, x, y and z in water at 298 K, the Henry's law constants (KH) are… (JEE Main 2019) | Canvas Classes