K2HgI4 is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is:
Solutions · Class 12 · JEE Main Previous Year Question
is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is:
- a
1.6
- b✓
1.8
- c
20
- d
22
1.8
Strategy:\n> Identify the number of ions produced by the dissociation of the complex and then apply the van't Hoff formula () using the given degree of ionisation.\n\nStep 1: Identify ions ()\n\nThe complex ion behaves as a single unit. Total ions = .\n\nStep 2: Calculate } i \text{\n.\n\n\n
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