JEE Main · 2021 · Shift-IeasySOL-032

Which one of the following 0.06 M aqueous solutions has lowest freezing point?

Solutions · Class 12 · JEE Main Previous Year Question

Question

Which one of the following 0.06 M aqueous solutions has lowest freezing point?

Options
  1. a

    Al2(SO4)3\mathrm{Al_2(SO_4)_3}

  2. b

    C6H12O6\mathrm{C_6H_{12}O_6}

  3. c

    KI

  4. d

    K2SO4\mathrm{K_2SO_4}

Correct Answera

Al2(SO4)3\mathrm{Al_2(SO_4)_3}

Detailed Solution

Strategy:\n> Freezing point is a colligative property. Lowest freezing point corresponds to the highest depression in freezing point (ΔTf\Delta T_f), which is achieved by the solution with the highest total concentration of particles (itimesMi \\times M).\n\nStep 1: Analyze dissociation for each solute\n1. \ceAl2(SO4)3\ce{Al2(SO4)3}: \ceAl2(SO4)32Al3++3SO42\ce{Al2(SO4)3 \rightarrow 2Al^3+ + 3SO4^2-} (i=5i = 5)\n2. \ceC6H12O6\ce{C6H12O6}: Non-electrolyte (i=1i = 1)\n3. \ceKI\ce{KI}: \ceKIK++I\ce{KI \rightarrow K+ + I-} (i=2i = 2)\n4. \ceK2SO4\ce{K2SO4}: \ceK2SO42K++SO42\ce{K2SO4 \rightarrow 2K+ + SO4^2-} (i=3i = 3)\n\nStep 2: Compare effective concentrations (itimesMi \\times M)\nGiven M=0.06M = 0.06 for all.\n1. 5times0.06=0.305 \\times 0.06 = 0.30\n2. 1times0.06=0.061 \\times 0.06 = 0.06\n3. 2times0.06=0.122 \\times 0.06 = 0.12\n4. 3times0.06=0.183 \\times 0.06 = 0.18\n\nConclusion:\n\ceAl2(SO4)3\ce{Al2(SO4)3} has the highest effective concentration, thus the lowest freezing point.\n\ntextAnswer:(1)\ceAl2(SO4)3\boxed{\\text{Answer: (1) } \ce{Al2(SO4)3}}

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