For electron in '2s' and '2p' orbitals, the orbital angular momentum values, respectively are:

🧠 Shape Over Energy Orbital angular momentum ($L$) is a measure of the "swirl" of an electron. It depends exclusively on the azimuthal quantum number ($l$), which determines the subshell's shape. The principal quantum number $n$ (shell energy) has no effect on this value.

🗺️ The Subshell Audit The formula is: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$

1. For '2s' orbital: Any $s$ orbital has $l = 0$. $L = \sqrt{0(0+1)} \frac{h}{2\pi} = 0$
2. For '2p' orbital: Any $p$ orbital has $l = 1$. $L = \sqrt{1(1+1)} \frac{h}{2\pi} = \sqrt{2} \frac{h}{2\pi}$ The values are 0 and $\sqrt{2} \frac{h}{2\pi}$ respectively.

⚡ The Quick "S" Zero Just remember: s = Zero. $L$ is zero for all $s$ orbitals. If the first value in an option isn't zero, cross it out immediately!

⚠️ Subscripts matter Ensure you don't confuse $h/2\pi$ with just $h$. The factor of $2\pi$ is part of the reduced Planck constant ($\hbar$) which is the fundamental unit for angular momentum.

$\boxed{\text{Answer: (d)}}$