JEE Main · 2023 · Shift-ImediumTHERMO-091

The enthalpy change for the adsorption process and micelle formation respectively are:

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

The enthalpy change for the adsorption process and micelle formation respectively are:

Options
  1. a

    ΔHads>0\Delta H_{ads}>0 and ΔHmic<0\Delta H_{mic}<0

  2. b

    ΔHads>0\Delta H_{ads}>0 and ΔHmic>0\Delta H_{mic}>0

  3. c

    ΔHads<0\Delta H_{ads}<0 and ΔHmic>0\Delta H_{mic}>0

  4. d

    ΔHads<0\Delta H_{ads}<0 and ΔHmic<0\Delta H_{mic}<0

Correct Answerc

ΔHads<0\Delta H_{ads}<0 and ΔHmic>0\Delta H_{mic}>0

Detailed Solution

🧠 Adsorption is exothermic; micelle formation is endothermic but entropy-driven Two processes, two opposite signs:

Adsorption: gas/solute molecules lose kinetic freedom and bond to a surface → energy is released → ΔHads<0\Delta H_{\text{ads}} < 0 (exothermic). ✓

Micelle formation: surfactant tails cluster together to escape the aqueous environment. The hydrophobic effect is primarily entropy-driven — the process actually has a slightly positive ΔHmic>0\Delta H_{\text{mic}} > 0 (endothermic). The large gain in entropy of the surrounding water molecules drives spontaneity. ✓

This matches option (c): ΔHads<0\Delta H_{\text{ads}} < 0 and ΔHmic>0\Delta H_{\text{mic}} > 0.

⚠️ Trap: Students expect both to be exothermic because both are "thermodynamically favourable." Micelle formation is spontaneous, but its enthalpy is positive — it's entropy that drives it.

Answer: (c)\boxed{\text{Answer: (c)}}

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