JEE Main · 2023 · Shift-ImediumTHERMO-091

The enthalpy change for the adsorption process and micelle formation respectively are:

Thermodynamics · Class 11 · JEE Main Previous Year Question

Question

The enthalpy change for the adsorption process and micelle formation respectively are:

Options
  1. a

    ΔHads>0\Delta H_{ads}>0 and ΔHmic<0\Delta H_{mic}<0

  2. b

    ΔHads>0\Delta H_{ads}>0 and ΔHmic>0\Delta H_{mic}>0

  3. c

    ΔHads<0\Delta H_{ads}<0 and ΔHmic>0\Delta H_{mic}>0

  4. d

    ΔHads<0\Delta H_{ads}<0 and ΔHmic<0\Delta H_{mic}<0

Correct Answerc

ΔHads<0\Delta H_{ads}<0 and ΔHmic>0\Delta H_{mic}>0

Detailed Solution

🧠 Adsorption is exothermic; micelle formation is endothermic but entropy-driven Two processes, two opposite signs:

Adsorption: gas/solute molecules lose kinetic freedom and bond to a surface → energy is released → ΔHads<0\Delta H_{\text{ads}} < 0 (exothermic). ✓

Micelle formation: surfactant tails cluster together to escape the aqueous environment. The hydrophobic effect is primarily entropy-driven — the process actually has a slightly positive ΔHmic>0\Delta H_{\text{mic}} > 0 (endothermic). The large gain in entropy of the surrounding water molecules drives spontaneity. ✓

This matches option (c): ΔHads<0\Delta H_{\text{ads}} < 0 and ΔHmic>0\Delta H_{\text{mic}} > 0.

⚠️ Trap: Students expect both to be exothermic because both are "thermodynamically favourable." Micelle formation is spontaneous, but its enthalpy is positive — it's entropy that drives it.

Answer: (c)\boxed{\text{Answer: (c)}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Thermodynamics) inside The Crucible, our adaptive practice platform.

The enthalpy change for the adsorption process and micelle formation respectively are: (JEE Main 2023) | Canvas Classes