The reaction in which the hybridisation of the underlined atom is affected is

Question

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Step 1 — Analyse each reaction:

(1)  disproportionation:
P in  is sp³ hybridized. In disproportionation products ( and ), P remains sp³. No change ✗

(2) :
S in  is sp³. Products are  and HCl. S remains sp³. No change ✗

(3) :
N in  is sp³; N in  is also sp³. No change ✗

(4) :
: Xe is sp³d² (6 electron pairs, square planar)
Product: 
: Xe has 3 bonds + 2 lone pairs = 5 electron pairs → sp³d hybridization
Hybridization changes from sp³d² to sp³d ✓

Answer: Option (4)

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