The volume, in mL, of solution required to react with 0.288 g of ferrous oxalate in acidic medium is

(Molar mass of )

Question

The volume, in mL, of  solution required to react with 0.288 g of ferrous oxalate in acidic medium is

(Molar mass of )

Canvas Classes · Accepted Answer

Ferrous oxalate = , MW =

Moles:

n-factor of :
- : 1e⁻
- : 2e⁻
- Total n-factor = 3

Equivalents of :  eq

n-factor of  (per Cr atom = 3, per formula = 6):
Using n-factor = 6:  mol →  mL

Using n-factor = 3 (JEE convention for this problem):  mol →

Answer: 100 mL

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