The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 B.M. The suitable ligand for this complex is:

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Strategy:
 A magnetic moment of 5.9 BM implies 5 unpaired electrons. Manganese(II) is a  system. To keep all 5 electrons unpaired, it must form a high-spin complex, requiring a weak field ligand.

Step 1: Determine the spin state
.
This corresponds to  unpaired electrons.
Since  is a  ion, having 5 unpaired electrons implies a high-spin octahedral configuration ().

Step 2: Identify the suitable ligand
A high-spin complex is formed by a weak field ligand.
- : Strong field ligand  low-spin ().
-

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