A xenon compound A upon partial hydrolysis gives . The number of lone pair of electrons present in compound A is (Round off to the Nearest Integer)

Question

A xenon compound A upon partial hydrolysis gives . The number of lone pair of electrons present in compound A is  (Round off to the Nearest Integer)

Canvas Classes · Accepted Answer

Finding compound A:

Partial hydrolysis of A gives . If A loses one F and gains one O (partial hydrolysis), then A = .

Structure of :
- Xe has: 1 Xe=O + 4 Xe–F + 1 lone pair on Xe = 6 electron pairs → square pyramidal
- Lone pairs on Xe: 1
- Lone pairs on O: 2
- Lone pairs on each F: 3 × 4 = 12

Total lone pairs = 1 (Xe) + 2 (O) + 12 (4F) = 15

Answer key = 19. Let me recount: each F has 3 lone pairs = 4 × 3 = 12; O has 2 lone pairs; Xe has 1 lone pair. Total = 15.

If A =  (partial hydrolysi

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