Some amount of dichloromethane () is added to 671.141 mL of chloroform () to prepare M solution of (DCM). The concentration of DCM is ppm (by mass).

Given: Atomic mass: C = 12; H: 1; Cl = 35.5; de

Question

Some amount of dichloromethane () is added to 671.141 mL of chloroform () to prepare  M solution of  (DCM). The concentration of DCM is  ppm (by mass).

Given: Atomic mass: C = 12; H: 1; Cl = 35.5; density of  = 1.49 g cm⁻³

Canvas Classes · Accepted Answer

Strategy:
 PPM (parts per million) by mass is calculated as . First, find the mass of DCM from its molarity and the volume, then the mass of the chloroform solvent using its density.

Step 1: Calculate the mass of the solvent (Chloroform, )
Volume = 671.141 mL, Density = 1.49 g/mL.

Step 2: Calculate the mass of the solute (DCM, )
- Molar mass of DCM = 
- Moles in solution () = Molarity  Volume (L)
-

Step 3: Calculate PPM
Assume total mass  solvent mass (1000 g) for very dilute solutions.

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