1 L, 0.02 M solution of is mixed with 1 L, 0.02 M solution of . The resulting solution is divided into two equal parts (X) and treated with excess AgNO₃ and BaCl₂ respectively:
1 L Solution (X) + AgN

Question

1 L, 0.02 M solution of  is mixed with 1 L, 0.02 M solution of . The resulting solution is divided into two equal parts (X) and treated with excess AgNO₃ and BaCl₂ respectively:
1 L Solution (X) + AgNO₃ (excess) → Y
1 L Solution (X) + BaCl₂ (excess) → Z
The number of moles of Y and Z respectively are:

Canvas Classes · Accepted Answer

Strategy:
 Track the moles of free (ionizable) ions present outside the coordination sphere in the resulting mixture.

Step 1: Analyze the initial solutions
- Solution A: 1 L of 0.02 M . This contains 0.02 moles of ionizable  (inside the sphere,  won't test).
- Solution B: 1 L of 0.02 M . This contains 0.02 moles of ionizable  (inside,  won't test).
Mixing these gives a total 2 L solution containing 0.02 moles of free  and 0.02 moles of free .

Step 2: Analyze the divided halves (X)
Dividing the

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