The vapour pressure of 30% (w/v), aqueous solution of glucose is mm Hg at 25°C.

[Given: The density of 30% (w/v), aqueous solution of glucose is 1.2 g cm⁻³ and vapour pressure of pure water is 24 mm

Question

The vapour pressure of 30% (w/v), aqueous solution of glucose is  mm Hg at 25°C.

[Given: The density of 30% (w/v), aqueous solution of glucose is 1.2 g cm⁻³ and vapour pressure of pure water is 24 mm Hg.]

(Molar mass of glucose is 180 g mol⁻¹)

Canvas Classes · Accepted Answer

Strategy:
 Convert the w/v% concentration into mole fraction (via masses and density) to calculate the vapour pressure using Raoult's Law ().

Step 1: Determine the composition
- 30% (w/v) means 30 g glucose in 100 mL solution.
- Mass of solution = .
- Mass of water = .

Step 2: Calculate Moles
- .
- .

Step 3: Calculate Mole Fraction of the solvent ()

Step 4: Calculate Vapour Pressure

Rounding to the nearest integer: 23.

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