Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained.

| Reading | Volume (mL) |
|---|---|
| (i) | 4.5 |
| (ii) | 4.5 |
| (

Question

Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained.

| Reading | Volume (mL) |
|---|---|
| (i) | 4.5 |
| (ii) | 4.5 |
| (iii) | 4.4 |
| (iv) | 4.4 |
| (v) | 4.4 |

If the volume of oxalic acid taken was 10.0 mL then the molarity of the NaOH solution is  M. (Rounded-off to the nearest integer)

Canvas Classes · Accepted Answer

Step 1 — Concordant titre value:
The concordant readings are 4.4 mL, 4.4 mL, 4.4 mL →  mL

Step 2 — Reaction:

Step 3 — Moles of oxalic acid:

Step 4 — Moles of NaOH (ratio 1:2):

Step 5 — Molarity of NaOH:

Answer: 6 M

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