The term independent of in the expansion of , where is equal to .

Question

The term independent of  in the expansion of , where  is equal to .

Canvas Classes · Accepted Answer

🧠 Same Identity as BNML-001 — Cubes Inside the Fractions

Read the bracket. Inside we have:

.

Both fractions simplify via algebraic identities.

First fraction: , and the denominator  is the "" companion. So the first fraction .

Second fraction: . Denominator . So the second fraction .

Difference: .

So the expression is . Same as BNML-001.

🗺️ Working It Out

General term: .

For independence: .

Coefficient: .

⚡ The Smart Move

Same factorisation as BNML-001:

- .
-  (when written with

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