Match List I with List II:

List I (Species): (a) (b) (c) (d)

List II (Hybridization): (i) (ii) (iii) (iv) (v) sp

Choose the correct answer:

Question

Match List I with List II:

List I (Species): (a)  (b)  (c)  (d)

List II (Hybridization): (i)  (ii)  (iii)  (iv)  (v) sp

Choose the correct answer:

Canvas Classes · Accepted Answer

Step 1 — Determine hybridization of each species:

(a) : S has 4 bonds + 1 lone pair = 5 electron pairs → sp³d → (iii)

(b) : I has 5 bonds + 1 lone pair = 6 electron pairs → sp³d² → (i)

(c) : N has 2 double bonds + 0 lone pairs = 2 electron pairs → sp → (v)

(d) : N has 4 bonds + 0 lone pairs = 4 electron pairs → sp³ → (iv)

Matching: (a)-(iii), (b)-(i), (c)-(v), (d)-(iv)

Answer: Option (3)

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