1 Faraday electricity was passed through (1.5 M, 1 L)/Cu and 0.1 Faraday was passed through (0.2 M, 1 L)/Ag electrolytic cells. After this the two cells were connected as shown below to make an elec

Question

1 Faraday electricity was passed through  (1.5 M, 1 L)/Cu and 0.1 Faraday was passed through  (0.2 M, 1 L)/Ag electrolytic cells. After this the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at 298 K is  mV.

Given: , ,

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Strategy:
 Determine the final concentrations of ions after electrolysis using Faraday's Laws. Then apply the Nernst Equation to calculate the potential of the combined galvanic cell.

Step 1: Concentrations After Electrolysis
- Copper Cell: . 1 Faraday passes.
 Moles of  consumed .
 Remaining .
- Silver Cell: . 0.1 Faraday passes.
 Moles of  consumed .
 Remaining .

Step 2: Calculate 
Cathode: , Anode: .
Reaction: , .

Step 3: Apply Nernst Equation

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