The homoleptic and octahedral complex of Co²⁺ and H₂O has unpaired electron(s) in the set of orbitals.

Question

The homoleptic and octahedral complex of Co²⁺ and H₂O has  unpaired electron(s) in the  set of orbitals.

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Strategy:
 Identify the d-electron configuration of the metal, observe the ligand field to determine the spin state, and distribute electrons within the  subset to count unpaired ones.

Step 1: Metal configuration
The complex is .
 has a  electron configuration.

Step 2: Crystal field splitting
 is a weak field ligand, forming a high-spin octahedral complex.
Configuration: .

Step 3: Analyze the  set
There are 5 electrons in the three  orbitals.
According to Hund's rule, they fill as: , , .
This

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