40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is K. (Nearest integer). [Given: ; Density of water = 1.00 g cm⁻³; Freezing point of water = 273.15 K]

Question

40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is  K. (Nearest integer). [Given: ; Density of water = 1.00 g cm⁻³; Freezing point of water = 273.15 K]

Canvas Classes · Accepted Answer

Strategy:
 Calculate the molality of the glucose solution and determine the freezing point depression.

Step 1: Calculate moles of glucose
- .

Step 2: Calculate molality ()
- Mass of water = 200 mL = 200 g = 0.2 kg.

Step 3: Calculate } \Delta Tf 	ext{

Step 4: Determine Freezing Point

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