The correct statement among the following is:

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Canvas Classes · Accepted Answer

Step 1 — Structure of :
- N has a lone pair that can donate into the empty d-orbitals of Si (pπ–dπ back bonding)
- This back bonding delocalises the lone pair into Si–N bonds
- N becomes sp² hybridized → planar structure (like BF₃)
- The lone pair is involved in back bonding → less available for protonation

Step 2 — Structure of :
- C has no empty d-orbitals → no back bonding
- N remains sp³ hybridized → pyramidal
- Lone pair is fully available → more basic

Step 3 — Comparison:
- : planar (sp²

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