For a d⁴ metal ion in an octahedral field, the correct electronic configuration is:

Question

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Strategy:
 Understand how the parameter  (pairing energy) vs  (crystal field splitting) dictates the spin state.

Step 1: Evaluate the options theoretically
A  configuration can have two fates in an octahedral field:
- If  (Weak field): It requires less energy to promote the 4th electron to the higher  orbital than to pair it. It becomes high spin: .
- If  (Strong field): It requires less energy to pair the electron in the lower  orbital than to promote it. It becomes low spin: .

Step 2: Check

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