During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is %.

(Given molar mass in of Ba: 137, S: 32, O: 16)

Question

During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is  %.

(Given molar mass in  of Ba: 137, S: 32, O: 16)

Canvas Classes · Accepted Answer

Step 1: Recall Carius Method for Sulphur Estimation

In the Carius method for sulphur, the organic compound is heated with fuming . Sulphur is oxidised to , which is then precipitated as barium sulphate:

Step 2: Determine Molar Masses

- Molar mass of  = 137 + 32 + 4(16) = 137 + 32 + 64 = 233 g/mol
- Atomic mass of S = 32 g/mol

Step 3: Calculate Mass of Sulphur in BaSO₄

Each mole of  contains one mole of S:

Step 4: Calculate Percentage of Sulphur

Mass of organic compound = 160 mg

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