The mass of sodium acetate () required to prepare 250 mL of 0.35 M aqueous solution is g.

(Molar mass of is 82.02 g mol⁻¹) Round off to the nearest integer.

Question

The mass of sodium acetate () required to prepare 250 mL of 0.35 M aqueous solution is  g.

(Molar mass of  is 82.02 g mol⁻¹) Round off to the nearest integer.

Canvas Classes · Accepted Answer

Strategy:
 The mass of a solute needed is calculated by finding the total number of moles (Molarity  Volume) and multiplying by the molar mass.

Step 1: Calculate the total moles of  required
- Molarity () = 0.35 mol/L
- Volume () = 250 mL = 0.25 L

Step 2: Calculate the mass
Molar mass = 82.02 g/mol.

Rounding to the nearest integer: 7 g.

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