An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with [Carius Method], the percentage of chlorine in compound A is when

Question

An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with  [Carius Method], the percentage of chlorine in compound A is  when it forms 0.3849 g of AgCl.

(Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)

Canvas Classes · Accepted Answer

Step 1: Recall Carius Method for Chlorine

Where molar mass of  = 107.87 + 35.5 ≈ 143.5 g/mol (using Ag = 107.87)

Step 2: Substitute Given Values

-  = 0.3849 g
-  = 0.5 g

Using the given atomic masses: Ag = 107.87, Cl = 35.5

Molar mass of AgCl = 107.87 + 35.5 = 143.37 g/mol

Step 3: Calculate Percentage

Answer: 19 (nearest integer)

Verification:

Key Points to Remember:
- When given Ag = 107.87 (not 108), use exact molar mass for AgCl = 143.37 g/mol
- The extra chlorination step (

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