50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. What is the amount of NaOH in 50 mL of the given sodium hydroxide solution?

Question

Canvas Classes · Accepted Answer

Step 1 — Reaction of oxalic acid with NaOH:

Step 2 — Moles of oxalic acid used:

Step 3 — Moles of NaOH in 25 mL (stoichiometry 1:2):

Step 4 — Molarity of NaOH solution:

Step 5 — Amount of NaOH in 50 mL of the same solution:

Answer: Option (2) — 4 g

More questions from Redox Reactions