The Total pressure observed by mixing two liquid A and B is 350 mm Hg when their mole fractions are 0.7 and 0.3 respectively. The Total pressure becomes 410 mm Hg if the mole fractions are changed to

Question

The Total pressure observed by mixing two liquid A and B is 350 mm Hg when their mole fractions are 0.7 and 0.3 respectively. The Total pressure becomes 410 mm Hg if the mole fractions are changed to 0.2 and 0.8 respectively for A and B. The vapour pressure of pure A is  mm Hg. (Nearest integer)

Consider the liquids and solutions behave ideally

Canvas Classes · Accepted Answer

Strategy:
 Use Raoult's law () to set up two simultaneous equations based on the two different mixing scenarios. Solving these will give the vapour pressures of the pure components.

Step 1: Set up the equations
1. Scenario 1: .
   
2. Scenario 2: .

Step 2: Solve the simultaneous equations
Multiply (Eq 1) by 8 and (Eq 2) by 3:
- 
- 
Subtracting the two:

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