2.7 kg of each of water and acetic acid are mixed. The freezing point of the solution will be . Consider the acetic acid does not dimerise in water, nor dissociates in water. (nearest integer)

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Question

2.7 kg of each of water and acetic acid are mixed. The freezing point of the solution will be . Consider the acetic acid does not dimerise in water, nor dissociates in water.   (nearest integer)

[Given: Molar mass of water = 18 g mol⁻¹, acetic acid = 60 g mol⁻¹; : 1.86 K kg mol⁻¹;  acetic acid: 3.90 K kg mol⁻¹; freezing point:  = 273 K, acetic acid = 290 K]

Canvas Classes · Accepted Answer

Strategy:
 When two components are mixed in equal mass, one acts as the solvent. We calculate the freezing point depression for both possible solvent scenarios (water as solvent vs. acetic acid as solvent). The solution will freeze when the first component starts to crystalize.

Step 1: Identify moles of each component
Mass = 2.7 kg = 2700 g.
- Moles of water () = 
- Moles of acetic acid () =

Step 2: Calculate depression using water as solvent
FP of pure water = 273 K (0°C).
- Molality () = 
-

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