When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is . (Nearest Integer)

Question

(Atomic mass: Ag = 108, Br = 80)

Canvas Classes · Accepted Answer

Step 1: Recall the Carius Method Formula for Bromine

Where:
- Molar mass of  = 108 + 80 = 188 g/mol
- Atomic mass of Br = 80 g/mol

Step 2: Substitute Given Values

-  = 0.2397 g
-  = 0.15 g

Step 3: Calculate Percentage

Answer: 68 (nearest integer)

Verification:

Key Points to Remember:
- 
- A high %Br (68%) suggests the compound has one or possibly two Br atoms (e.g., CHBr₃ has 94% Br)
- AgBr molar mass: 108 (Ag) + 80 (Br) = 188 g/mol (not 187 or 189!)
- Always double-check molar mas

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