When 12 g carbon is burnt in 48 g of oxygen (), the volume of CO produced is at STP. [Molar volume=22.7 L/mol; C=12, O=16]

Question

When 12 g carbon is burnt in 48 g of oxygen (), the volume of CO produced is   at STP. [Molar volume=22.7 L/mol; C=12, O=16]

Canvas Classes · Accepted Answer

Strategy:
 Reaction: . Identify the limiting reagent and then calculate the volume of Nitrogen monoxide product at STP using its stoichiometric coefficient ( or  relative to Carbon).

Step 1: Calculate initial moles
- Moles C .
- Moles .
According to ,  C needs  . We have excess oxygen, so Carbon is limiting.

Step 2: Calculate yield and volume at STP
From 1 mole C, 1 mole of  is produced.

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